Decision Errors
IMS2 Ch. 14
Math 115
CPR Study
- Research question: Do blood thinners affect survival rate in heart attack patients that have received CPR?
cpr data set is available here
- 2 variables
- group: treatment (received blood thinner) or control (did not)
- outcome: died or survived (for at least 24 hours)
- 90 patients (40 treatment, 50 control, randomly assigned)
Hypotheses
- Blood thinners can be administered to treat a clot that is causing a heart attack
- CPR can cause internal injuries
- Blood thinners can make it more difficult for these injuries to heal
- Do blood thinners affect survival in a positive or negative way?
- Alternative hypothesis reflects the fact that we don’t have expectations about the direction of the relationship
Two-sided hypothesis test
Example of one-sided hypothesis test
Results (EDA)
| control |
39 |
11 |
50 |
| treatment |
26 |
14 |
40 |
| total |
65 |
25 |
90 |
Difference in proportions
- Success: outcome = “survived”
- Statistic of interest: difference in proportions \[\hat{p}_T-\hat{p}_C\]
- Observed difference: \[\frac{14}{40}-\frac{11}{50}=0.13\]
Z Score
- SE = 0.0955 (more on estimating this in Ch. 17)
- Thus, \[Z = \frac{0.13-0}{0.0955} = 1.36\]
Hypothesis test
- Technical conditions met for using a normal approximation for the null distribution
- Since we calculated \(Z\), we can use the standard normal distribution \(N(0,1)\)
- We will use significance level \(\alpha=0.05\)
p-value for 2-sided test
- As with a 1-sided test, the p-value is the probability of observing a value of the statistic that is at least as extreme as the observed value, assuming the null hypothesis is true
- With a 2-sided test, extreme values are in both tails of the null distribution
![]()
Density function standard normal distribution with left tail shaded below Z=1.36.
![]()
Density function standard normal distribution with right tail shaded above Z=1.36.
- p-value is \(2\times0.0869 = 0.1738\)
- Since the p-value is greater than 0.05, we do not reject the null hypothesis
- It is plausible that there is no difference in survival rates between the two groups
- Note: The p-value is twice as large for a two-sided test than for a one-sided test
- With a symmetric null distribution (like the normal distribution) that is centered at 0, the two tails are symmetric
- Thus, for example, the p-value is also equal to the sum of the areas in the two tails that are to the left of -1.36 to the right of 1.36
![]()
Density function standard normal distribution tails shaded below Z=-1.36 and above Z=1.36.
Decision Errors
- There are two types of errors we can make in a hypothesis test
- Type 1 Error occurs if we conclude that the null hypothesis is false when it is not (false alarm)
- Type 2 Error occurs if we fail to reject the null hypothesis even though it is false (missed opportunity)
Controlling Type 1 Errors
- Type 1 Error is typically considered more severe
- The probability of making a type 1 error (assuming the null is true) is equal to the significance level
- Can reduce \(\alpha\) to make type 1 errors less likely
Controlling Type 2 Errors
- There is a trade-off between the two types of errors
- Decreasing probability of type 1, increases the probability of type 2
- Power is the probability of rejecting the null hypothesis if the alternative is true
- Higher power reduces the chance of making a type 2 error
- Power is related to effect size (easier to detect larger effects), sample size (larger sample results in more power), among other things
Relationship between CI and Hypothesis tests
- A significance level of \(\alpha\) for a 2-sided hypothesis test corresponds to a confidence level of \(1-\alpha\)
- E.g., \(\alpha = 0.05\) corresponds to a 95% confidence interval
- If we would reject the null hypothesis at \(\alpha=0.05\), then the 95% confidence interval would not contain the null value
- Conversely, if we calculate the 95% confidence interval first and find that it does not contain the null value, then we would reject the null hypothesis at \(\alpha=0.05\) with a two-sided test
- In the CPR study, we did not reject the null hypothesis at \(\alpha=0.05\) (p-value = 0.1738)
- Even though we did not calculate a confidence interval for the difference in survival proportions, we know that the 95% confidence interval would contain 0 (the value under the null hypothesis)