From the sample it appears that there is a stronger preference for cola on the East Coast
It may be that there is no real difference in preference in the population, and the observed difference is not surprising when selecting a sample of this size from the population
A hypothesis test states these two possibilities formally as hypotheses then weighs them against each other using the results from the sample as evidence
Hypotheses
The null hypothesis, denoted \(H_0\), represents a skeptical perspective or a claim of no difference
The alternative hypothesis, denote \(H_A\), represents an alternative claim of difference.
As statisticians, we usually establish hypotheses before viewing the data in order to avoid bias
In words:
\(H_0:\) Location has no
effect on preference for
cola over orange soda.
\(H_A:\) There is a higher
preference for cola
over orange soda on the
East Coast than on the
West Coast.
In symbols:
\(H_0: p_E - p_W = 0\) \(H_A: p_E - p_W > 0\)
Null Distribution
We test the null hypothesis by comparing the observed value of the statistic to a null distribution
If the null hypothesis is true and we select different samples of the same size from the population, we would expect the value of the statistic to vary between samples
The null distribution is the distribution that describes those values
It is an example of a sampling distribution (distribution of a statistic)
Simulating the Null Hypothesis
To test our cola preference hypothesis, we need to compare our observed difference (0.093) to what we’d expect if there really was no regional difference
We can simulate “no difference” by mixing up the cola preferences and randomly reassigning them to East Coast and West Coast
Each of these shuffles is called a random permutation
Shuffling Cards to Simulate the Null Hypothesis
Original Samples
Shuffling...
East Coast (34 people)
Cola: 28
Orange: 6
Proportion Cola: 0.824
West Coast (26 people)
Cola: 19
Orange: 7
Proportion Cola: 0.731
Difference in Proportions: 0.824 - 0.731 = 0.093← Original Data
Distribution of Differences
Red circle shows original difference (0.093). Blue circles show permutation differences.
Building the Null Distribution
Red line shows original difference (0.093). Gray bars show permutation differences.
Dot plot of 100 differences in randomized proportions (null distribution), showing observed difference as dashed vertical line.
Random Permutations with a Computer
We can use computers to create thousands of random permutations
With a computer, we don’t actually shuffle cards. Instead we randomly permute the values of the response variable
Each permutation gives us one possible difference under the assumption that region doesn’t matter
The distribution of these differences is the null distribution
Here is the original soda data with 5 random permutations of the response variable.
p-Value
To test the null hypothesis (\(p_E-p_W = 0\)) we consider how probable it would be to get a difference in proportions that is at least as large as the observed difference if \(H_0\) is true
This probability is called a p-value
We use the null distribution to calculate the p-value
There are 28 differences in randomization proportions that are greater than or equal to the observed value (0.09276). So we estimate the p-value to be 28/100 = 0.28.
Dot plot of 100 differences in randomized proportions (null distribution), showing observed difference as dashed vertical line.
Significance Level
Before we conduct a study, we define a significance level, denoted \(\alpha\)
We decide that in order to reject the null hypothesis as false, the p-value must be less than \(\alpha\)
The significance level is the standard of evidence we will use to judge the null hypothesis
We presume the null hypothesis is true, but we are willing to reject it if the evidence against it is strong enough (the p-value is less than \(\alpha\))
Typical values for \(\alpha\) are 0.05 and 0.01
Sometimes other values are used
Unless otherwise noted, we will always use \(\alpha = 0.05\)
Conclusion
In the soda example, the observed difference in proportions (\(\hat{p}_E-\hat{p}_W = 0.09276\)) does not allow us to reject the null hypothesis (p = 0.28) at the \(\alpha = .05\) significance level.
The difference in the proportions is not statistically significant
This means that it is plausible that there is no difference in the proportions of people who prefer cola to orange soda between the East and West Coast.